Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False - python3
def is_leap(year):
leap = False
if (year % 4 == 0) and (year % 100 != 0):
leap = True
elif (year % 100 == 0) and (year % 400 != 0):
leap = False
elif (year % 400 == 0):
leap = True
else:
leap = False
return leap
year = int(input("Input Year :"))
print(is_leap(year))
